Question

This is about the "Law of Cosines", hopefully someone can help.
In △ABC,a=14, b=17, and c=22. Find m∠A.

Answer 1

Answer:

I dont go and ask to any teacher

Answer 2

Answer:C

Step-by-step explanation:

The law of cosines is: a^2 = b^2+c^2-2abcosA

14^2 = 17^2+22^2-2(17)(22)cosA

196 = 289 + 484 - 2(17)(22)cosA (we now subtract 289 from 196)

-93 = 484 - 2(17)(22)cosA (now we subtract 484 from -93)

-577 = -2(17)(22)cosA (we no divide -577 by the product of -2(17)(22) which is -748)

-577/-748 (since both are negative you can make them positive)

577/748=cos^-1A

39.52 = Angle A