this is an question of quadrilateral . Please solve this question I have doubt in this question .
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Let each angle = a, b, c, & d.
Now in any quadrilateral angle a + b + c + d= 360°
In the figure a=135° b= [x-38]° c=87° d= (x-18)°
So, 135 + (x-38)+87+(x-18)=360
222+2x-56=360
2x=360-166
x= 97
Hence a= 135° b=97-38=59° c=87°. d= 97-18=79°.
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Answer:
135° + 87° + (x - 38)° + (x- 18)° = 360°
222 + x - 38 + x - 18 = 360°
222 + 2x - 56 = 360°
166 + 2x = 360
2x = 360 - 166
2x = 194
x = 97°
now,
x - 38 = 97 - 38 = 59°
x - 18 = 97 - 18 = 79°
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