this is arithmetic progression (A.P) pls solve no. 3 question , thankyou
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Equating the an and an
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rahul1003:
thankyou for trying but it is wrong but it's okay i got the solution ! thnx
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A.T.Q
an of 1st AP = an of 2nd AP
231+(n-1)(228-231)= 3+(n-1)(9-6)
231+(n-1)×(-3) = 3+(n-1)×3
231-3n+3 = 3+3n-3
234-3n = 3n
234 = 3n+3n
234 =6n
39 = n
if you find it helpful please mark it as brainlist
an of 1st AP = an of 2nd AP
231+(n-1)(228-231)= 3+(n-1)(9-6)
231+(n-1)×(-3) = 3+(n-1)×3
231-3n+3 = 3+3n-3
234-3n = 3n
234 = 3n+3n
234 =6n
39 = n
if you find it helpful please mark it as brainlist
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