Math, asked by prasunkumar3221, 1 year ago

THIS IS BRAINLIEST QUESTION. ​

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Answers

Answered by Avanti112
0

Step-by-step explanation:

the area of the rhombus is 4× side

4 \times 61 = 244

the area of rhombus is 244.

Answered by JoshuaFerns
0

Hey there,

Please find below the answer to your given question.

Given:

A rhombus ABCD where:

i) AB = BC = CD = AD = 61 cm

ii) Diagonals AC and BD = 22 cm intersect at O.

To Find:

i) AC

ii) ar(ABCD)

Solution:

Diagonals of a Rhombus bisect each other at 90°.

=> ∠COD = 90°, BO = DO = 22/2 = 11cm, AO = CO

In right ΔCOD,

OD² + OC² = CD²

=> 11² + OC² = 61²

=> 121 + OC² = 3721

=> OC² = 3721 - 121

=> OC² = 3600

=> OC = 60 cm.

But, Diagonal AC = OC + AO

=> AC = OC + OC [ OC = OA, as proved above]

=> AC = 2OC

=> AC = 2(60)

=> AC = 120 cm

We know, ar(Rhombus) = (Diagonal 1 x Diagonal 2)/2

ar(ABCD) = (AC x BD)/2

=> 22 * 120 /2

=> ar(ABCD) = 1320 sq. cm

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Hope it helps.

Have a great day! ;)

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