Question

this is from ch exponents of 8th maths book icse how to solve it​

Answer 1

${ \frac{3 {x}^{ - 2} }{2 {y}^{ - 1} } }^{ - 2} \\ = \\ {\frac{3y}{2 {x}^{2} }}^{ - 2} \\ = \\ \frac{4 {x}^{4} }{9 {y}^{2} }$

Therefore this is outy solution

Answer 2

Step-by-step explanation:

3X to the power 4

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2 Y square