Question

This is from simultaneous equation ....plzz answer....thnk u

Answer 1

Let rohit have Rs x and ajay have Rs y
a/q x+100=2y
→x =2y-100.
a/q y+10=6x. eq1
Substituting the value of x in eq 1
y+10=6 *(2y-100)
→y+10= 12y -600
→y-12y=600-10
→11y =590
→y=590divided by 11
→y=53.64
Now by putting the value of y in eq 1 find x

Answer 2

Hi friend, Here is the required answer:-

Let Rohit's money be x and Ajay's be y.

According to question:-

(x+100)= 2(y-100) => x-2y= -200-100 => x-2y= -300 ----------(1)

6(x-10) = y+10 => 6x-y= 10+60=> 6x-y= 70 -------(2)

Multiplying Eq.(1) by 6,

6x-12y= -1800 --------(3)

Subtracting Eq(2) from (3),

6x -12y = 70
6x - y. = -1800
----------------------
-11y = 1870
y= 170 rupees.

x-2y= -300
x= -300 +340
x= 40 rupees.

VERIFICATION:- x-2y= -300 => 40- 340= -300

Hope this helps you...