Question

this is important pls say fast

Answer 1

Ans.

$\frac{sin \alpha + cos \alpha }{sin \alpha - cos \alpha } = \frac{5}{3}$
Now we divide the LHS's both nominator and denominator by
$cos \alpha$
Then, we get
$\frac{tan \alpha + 1 }{tan \alpha - 1} = \frac{5}{3} \\ or. \: 3tan \alpha + 3 = 5tan \alpha - 5 \\ or. \: 2tan \alpha = 8 \\ or. \: tan \alpha = 4$
We put the value
$tan \alpha = 4$
in the given expression.
Hence,
$\frac{7tan \alpha + 2}{ 2tan\alpha + 7} \\ = \frac{(7 \times 4 )\: + \: 2}{(2 \times 4 )\: + 7} \\ = \frac{30}{15} \\ = 2$
I hope that this helps you.