This is long division please do fastly
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f(x) = x3 + 13x2 + 32x + 20
-2 is a zero of f(x), so x+2 will be factor of f(x)
On long division of f(x) by x+2 we get
So, f(x) = x3 + 13x2 + 32x + 20
= (x2 + 11x + 10)(x + 2)
= (x2 + 10x + x + 10)(x + 2)
= (x + 10)(x + 1)(x + 2)
Hence f(x)=0 if x+10 =0 or x+1=0 or x+2=0
Therefore, the zeroes of the polynomial are -1, -10, -2.
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