Question

this is my question ​

Answer 1

Step-by-step explanation:

ABCD is a trapezium

AB = 20cm , BC = 13cm , DC = 25cm and CP = 5cm

As, ∠BPC = 90°

△BPC is a right angled triangle.

By Pythagoras Theorem:-

⇢ BC² = CP² + BP²

⇢ BP² = BC² - CP²

⇢ BP² = 13² - 5²

⇢ BP² = 169 - 25

⇢ BP = 144

⇢ BP = √144 = 12cm.

Distance between the parallel sides = 12cm

(Or) Height of the trapezium = 12cm

Area of trapezium = ½ × (sum of parallel sides) × Height

= ½ × (AB + CD) × BP

= ½ × (20 + 25) × 12

= 45 × 6

= 270

∴ The area of the trapezium = 270m²