Question

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Answer 1

Step-by-step explanation:

Draw a ray BX and cut off a line segment BC = 7cm; from it.

At B; construct angle YBX = 75°

With B as centre and radius = 12 cm (because AB + AC = 12cm) draw an arc to meet BY at D.

Join CD.

Draw Perpendicular bisector PQ of CD intersecting BD at A.

Join AC.

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Answer 2

Answer:

Figure Attached Along with Solution.

Step-by-step explanation:

Construct a triangle ABC in which BC = 6.3 cm, ∠B = 75° and AB + AC =9cm.

Given:

In ΔABC,

BC = 6.3cm

∠B = 75°

AB + AC = 9 cm.

Steps of Construction:

1) Draw the base BC = 6.3 cm.

2) At the point B, make an angle XBC = 75°.

3) Cut a line segment BD equal to AB + AC (= 9 cm) from the ray BX.

4) Join DC.

5) Make ∠DCY = ∠BDC.

6)Let CY intersect BX at A

THen ABC is the Required Triangle .