Question

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Answer 1

Given: Force one = F
Force two = 2F
Resultant = 2F

Using Law of parallelogram of forces

|R| = sqrt (|P|^2 + |Q|^2 +2|P||Q| cos θ) …………(1)
where θ is angle between the two forces.

Inserting given values in (1) we get

2F = sqrt (F^2 + (2F)^2 + 2 F (2F) cos θ)
squaring both sides we get

4F^2 = 5F^2 + 4F^2 cos θ

or 4 cos θ = -1

or θ = arc cos (-1/4)

or θ = 104.5 deg

Hope this helps...
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