Question

This is number which is greater then the aggregate of its third, 10th & 12th part by 58. find the number.

Answer 1

Number is N.

$N - \frac{N}{3}-\frac{N}{10}-\frac{N}{12} = 58 \\ \\ N* [ 1 - \frac{1}{3} - \frac{1}{10} - \frac{1}{12} = 58 \\ \\ N * \frac{60 - 20 - 6 - 5}{60} = 58 \\ \\ N * \frac{29}{60} = 58 \\ \\ N = 58 * \frac{60}{29} \\ \\ N = 2 * 60 = 120$