Math, asked by coolboi79, 1 year ago

THIS IS OF CHAPTER RATIONAL ND IRRATIONAL NOS Please find no. (iv) ​

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Answered by omprakash5744
1

given:

=> (3+2)/(3-2)

Rationalizing the denominator

=> (3+2)/3-2) × (3+2)/(3+2)

=> (3+2) square/(3) square-(2) square

=> {(3) square+(2) square

+ 2.3.2}/3-2

=> (3+2+26)/1

=> 5+26 Answer

hope it helps you

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Answered by satishraj29
1

Answer:

 \frac{ \sqrt{3 }  +  \sqrt{2} }{ \sqrt{3}  -  \sqrt{2} }  \times  \frac{ \sqrt{3}  +  \sqrt{2} }{ \sqrt{3 } +  \sqrt{2}  }  \\   \\  \frac{( \sqrt{3} +  \sqrt{2}) {}^{2}   }{1 }  \\  \\ ( \sqrt{3} ) {}^{2}  + ( \sqrt{2} ) {}^{2}  + 2. \sqrt{3} . \sqrt{2 }  \\ 3 + 2 + 2 \sqrt{6}  \\ 5 + 2 \sqrt{6}


satishraj29: thank brothers
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