Question

this is ques. above one
​

Answer 1

Solution

Let

• Selling price (SP) of article be x
• profit (P)% = 17%

If Selling price (SP) is increased by 33.60

• then Selling price (SP) = x+33.60
• After increasing the Selling price (SP) profit% also increase by 29%

therefore

$\\{ \sf\dfrac{Selling~ price}{100 + Profit\%}=\dfrac{After ~increase~price}{100 + After ~increase~price~Profit\%}}$

Putting the Value,we get

$\\{~~~~ \sf\dfrac{x}{100 + 17}=\dfrac{x + 33.60}{ 100 + 29}}$

${ →\sf\dfrac{x}{117}=\dfrac{x + 33.60}{ 129}}$

${ →\sf x \times 129 = 117(x + 33.60)}$

${→ \sf 129x = 117x + 3931.2}$

${ →\sf 129x - 117x = 3931.2}$

${→ \sf 12x = 3931.2}$

${ →\sf x = \cfrac{3931.2}{12} }$

${ →\sf x = 327.6}$

Therefore,

• the Selling price (SP) of an article = 327.6.

Now we need to Cost price (CP)

Here

• Selling price= 327.6.
• Profit%= 17%

we know that

$\pink{\sf CP=\dfrac{sp×100}{100+P\%}}$

${→\sf CP=\dfrac{327.6×100}{100+17}}$

${→\sf CP=\dfrac{32760}{117}}$

${→\sf CP=280}$

• The Cost Price Of An Article Be Rs.280.

Answer 2

Answer:

Let

Selling price (SP) of article be x

profit (P)% = 17%

If Selling price (SP) is increased by 33.60

then Selling price (SP) = x+33.60

After increasing the Selling price (SP) profit% also increase by 29%

therefore

\begin{gathered}\\{ \sf\dfrac{Selling~ price}{100 + Profit\%}=\dfrac{After ~increase~price}{100 + After ~increase~price~Profit\%}}\\\end{gathered}

100+Profit%

Selling price

=

100+After increase price Profit%

After increase price

Putting the Value,we get

\begin{gathered}\\{~~~~ \sf\dfrac{x}{100 + 17}=\dfrac{x + 33.60}{ 100 + 29}}\end{gathered}

100+17

x

=

100+29

x+33.60

{ →\sf\dfrac{x}{117}=\dfrac{x + 33.60}{ 129}}→

117

x

=

129

x+33.60

{ →\sf x \times 129 = 117(x + 33.60)}→x×129=117(x+33.60)

{→ \sf 129x = 117x + 3931.2}→129x=117x+3931.2

{ →\sf 129x - 117x = 3931.2}→129x−117x=3931.2

{→ \sf 12x = 3931.2}→12x=3931.2

{ →\sf x = \cfrac{3931.2}{12} }→x=

12

3931.2

\begin{gathered}{ →\sf x = 327.6}\\\end{gathered}

→x=327.6

Therefore,

the Selling price (SP) of an article = 327.6.

Now we need to Cost price (CP)

Here

Selling price= 327.6.

Profit%= 17%

we know that

\pink{\sf CP=\dfrac{sp×100}{100+P\%}}CP=

100+P%

sp×100

{→\sf CP=\dfrac{327.6×100}{100+17}}→CP=

100+17

327.6×100

{→\sf CP=\dfrac{32760}{117}}→CP=

117

32760

{→\sf CP=280}→CP=280

The Cost Price Of An Article Be Rs.280.

Step-by-step explanation:

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$Let</p><p></p><p>Selling price (SP) of article be x</p><p></p><p>profit (P)% = 17%</p><p></p><p>If Selling price (SP) is increased by 33.60</p><p></p><p>then Selling price (SP) = x+33.60</p><p></p><p>After increasing the Selling price (SP) profit% also increase by 29%</p><p></p><p>therefore</p><p></p><p>\begin{gathered}\\{ \sf\dfrac{Selling~ price}{100 + Profit\%}=\dfrac{After ~increase~price}{100 + After ~increase~price~Profit\%}}\\\end{gathered}100+Profit%Selling price=100+After increase price Profit%After increase price</p><p></p><p>Putting the Value,we get</p><p></p><p>\begin{gathered}\\{~~~~ \sf\dfrac{x}{100 + 17}=\dfrac{x + 33.60}{ 100 + 29}}\end{gathered}    100+17x=100+29x+33.60</p><p></p><p>{ →\sf\dfrac{x}{117}=\dfrac{x + 33.60}{ 129}}→117x=129x+33.60</p><p></p><p>{ →\sf x \times 129 = 117(x + 33.60)}→x×129=117(x+33.60)</p><p></p><p>{→ \sf 129x = 117x + 3931.2}→129x=117x+3931.2</p><p></p><p>{ →\sf 129x - 117x = 3931.2}→129x−117x=3931.2</p><p></p><p>{→ \sf 12x = 3931.2}→12x=3931.2</p><p></p><p>{ →\sf x = \cfrac{3931.2}{12} }→x=123931.2</p><p></p><p>\begin{gathered}{ →\sf x = 327.6}\\\end{gathered}→x=327.6</p><p></p><p>Therefore,</p><p></p><p>the Selling price (SP) of an article = 327.6.</p><p></p><p>Now we need to Cost price (CP)</p><p></p><p>Here</p><p></p><p>Selling price= 327.6.</p><p></p><p>Profit%= 17%</p><p></p><p>we know that</p><p></p><p>\pink{\sf CP=\dfrac{sp×100}{100+P\%}}CP=100+P%sp×100</p><p></p><p>{→\sf CP=\dfrac{327.6×100}{100+17}}→CP=100+17327.6×100</p><p></p><p>{→\sf CP=\dfrac{32760}{117}}→CP=11732760</p><p></p><p>{→\sf CP=280}→CP=280</p><p></p><p>The Cost Price Of An Article Be Rs.280.</p><p></p><p>$