Question

THIS IS QUESTION:-
$9 \sec {}^{2} a - 9 \tan {}^{2} a \: is \: equal \: to$
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Answer 1

Answer:

$9 { \sec}^{2} a - 9 { \tan }^{2} a = 9$

Step-by-step explanation:

we have , 9sec²a - 9tan²a

Let r = 9sec²a - 9tan²a

r = 9(sec²a - tan²a)

we know that,

sec²a - tan²a = 1

Therefore ,

r = 9 × 1

r = 9.

Hope it is helpful to you

Answer 2

Step-by-step explanation:

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