Question

This is the 2nd time I'm asking this question... please help me out

Answer 1

We have Equation for trajectory-------

$y = xtan \: theta \: - \frac{1}{2} \frac{gx {}^{2} }{u {}^{2}cos {}^{2} theta}$
or
$y = xtan \: theta - \frac{x {}^{2} }{2u {}^{2} cos {}^{2}theta \frac{1}{g} }$
or
$y = xtan \: theta - \frac{x {}^{2} }{2u {}^{2} cos \: theta \: sin \: theta \frac{1}{g} } \frac{sintheta}{costheta}$
or
$y = xtantheta - \frac{x {}^{2} tantheta}{range}$
or
$y = xtantheta(1 - \frac{x}{range} )$

Here...

range =x1 + x2

so putting the values we get.....


y=x1.tan(theta)[1 - x1/(x1 + x2)]

or y= x1.tan theta.[x2/(x1+x2)]

=> y=x1x2/(x1+x2) . tan theta.


that is option (b)