Question

this is the answer on the picture ​

Answer 1

Answer:

Proof of Gauss’s Theorem Statement:

Let the charge be = q

Let us construct the Gaussian sphere of radius = r

Now, Consider , A surface or area ds having having ds (vector)

Normal having the flux at ds:

Flux at ds:

d e = E (vector) d s (vector) cos θ

But , θ = 0

Therefore, Total flux:

C = f d Φ

E 4 π r2

Therefore,

σ = 1 / 4πɛo q / r2 × 4π r2

σ = q / ɛo

Answer 2

Its coordinate in meters is given by x(t) = 75t - 1.0t3 , where t is in s. When velocity (v) of the object = 0, the. value of its acceleration is : (Ans: -30 m/s2 )

• OK SIR I JOIN...