Question

this is the figure find OA ​

Answer 1

using Pythagoras,

${cd}^{2} + {cb}^{2} = {bd}^{2}$
$= > {9}^{2} + {12}^{2} = {bd}^{2}$
$= > 81 + 144 = {bd}^{2}$
$= > 225 = {bd}^{2}$
$= > 15 = bd$
$similarly \: we \: \: get \: ac$
$hence \: side \: oa \: = \frac{15}{2}$
$oa = 7.5cm$
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Answer 2

$<font color="red">HEY MATE</font>$

$<font color="blue"><marquee>YOUR SOLUTION</marquee></font>$

In triangle CAD

D=90°

AD=12cm

CD=9cm

${ac}^{2} = {ad}^{2} + {cd}^{2}$

$ac = \sqrt{ {ad}^{2} + {cd}^{2} }$

$= \sqrt{ {12}^{2} + {9}^{2} } \\ = \sqrt{144 + 81} \\ = \sqrt{225} = 15$

AC=15cm

AO=AC/2=15/2=7.5

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