This is the method of elimination by substitute in simultaneously equation chapter. The question is--
X-Y=10
2X+4Y=16
Plz give me the answer immediately
Answers
Answered by
2
Answer:
Step-by-step explanation:
X-Y=10
X=10+Y...........(i)
2X+4Y=16
according to eq(i),
2(10+Y)+4Y=16
20+2Y+4Y=16
20+6Y=16
6Y=16-20
6Y=-4
Y=-4/6
now you will get the answer to y
then fill the value of y again in eq(i)..
you will then get the value of x.
thats it friend..
hope its helpful....
gurbains23:
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Answered by
1
x - y =10 (eq1)
2x + 4y = 16 (eq2)
From eq 1 we get :
x= 10 + y (eq3)
Put the value of eq 3 in eq 2
2 × 10 + y + 4y = 16
20 + 2y + 4y = 16
20 + 6y = 16
6y = 16 - 20
6y = -4
y = -4\6
y = -2\3
Put the value of y in eq 2 we get :
x - y = 10
x + 2\3 = 10
x = 10 × 3\2
x = 15
Hence the value of x and y are :
x = 15
and
y = -2\3
Hope it will help u
Thank u
2x + 4y = 16 (eq2)
From eq 1 we get :
x= 10 + y (eq3)
Put the value of eq 3 in eq 2
2 × 10 + y + 4y = 16
20 + 2y + 4y = 16
20 + 6y = 16
6y = 16 - 20
6y = -4
y = -4\6
y = -2\3
Put the value of y in eq 2 we get :
x - y = 10
x + 2\3 = 10
x = 10 × 3\2
x = 15
Hence the value of x and y are :
x = 15
and
y = -2\3
Hope it will help u
Thank u
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