this is the q plzz ans it
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Hey!!!
I'm here as promised
_______________
We have
=> f(x) = x³ - 6x² + 3x + 10
Zeros => a , a + b and a + 2b
Thus the zeros are in AP
(This is a concept taught to you in class 10 later in the chapter Arithmetic Progression)
Let the zeros be a - d , a and a + d
We know,
Sum of zeros = -b/a
=> a - d + a + a + d = 6
=> 3a = 6
=> a = 2 (Answer)
We know
Product of zeros = -d/a
=> a(a - d)(a + d) = -10
=> a(a² - d²) = -10
=> 2(4 - d²) = -10
=> 4 - d² = -5
=> d² = 9
=> d = 3
=> b = 3 (Answer)
Thus zeros
=> a - d , a and a + d
=> - 1 , 2 and 5
______________
Hope this helps ✌️
I'm here as promised
_______________
We have
=> f(x) = x³ - 6x² + 3x + 10
Zeros => a , a + b and a + 2b
Thus the zeros are in AP
(This is a concept taught to you in class 10 later in the chapter Arithmetic Progression)
Let the zeros be a - d , a and a + d
We know,
Sum of zeros = -b/a
=> a - d + a + a + d = 6
=> 3a = 6
=> a = 2 (Answer)
We know
Product of zeros = -d/a
=> a(a - d)(a + d) = -10
=> a(a² - d²) = -10
=> 2(4 - d²) = -10
=> 4 - d² = -5
=> d² = 9
=> d = 3
=> b = 3 (Answer)
Thus zeros
=> a - d , a and a + d
=> - 1 , 2 and 5
______________
Hope this helps ✌️
sowmiya7:
this question is from polynomials
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