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1. <A=<C is true since These are two opposite angles of the parallelogram.
2. <FAB =1/2<A is true since AF bisects <A.
3. <DCE =1/2 <C is ture since CE bisects <C.
4. <FAB = < DCE is true
since, <A=<C => 1/2<A =1/2<C => <FAB=<DCE {from 2 and 3}
5. <DCE=<CEB is true since these angles are alternate angles where AB||CD and CF is a transversal.
6. <CEB=<FAB is true . from 4 and 5 we get it.
7. CE||AF is true. From 6 , <CEB=<FAB and these are corresponding angles where AB is a transversal of line CE and AF . so, CE||AF.
8. AE||FC is true.
AB||CD => AE||FC.
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