Question

This is the question ........

Answer 1

here RT||PQ

so we can write that angle PQR=TRS=50°

so angle PRQ=180-50-65=65

SO also PRT =180-50-65=65

Answer 2

here we will Note that <TRP is equal to a< PRQ
so <TRP+<PRQ+<TRS=180° ( linear pair)
2 <TRP +<TRS=180° ( from above)
2 < TRP +50°=180°
2 < TRP = 180° - 50°
2 <TRP=130°
< TRP=65°
< PRQ =65°
& <PQR=50°