Question

this is the question..

Answer 1

let the first term be ‘a’ and the common difference be ‘d’.
Given, 6th term=-10
»a+(6-1)d =-10
»a+5d=-10---(1)
and 10th term =-26
»a+(10-1)d=-26
»a+9d=-26----(2)
(2)-(1) we get
»(a+9d)-(a+5d)=-26-(-10)
»a+9d-a-5d=-26+10
»4d=-16
»d=-16/4
»d=-4

Putting d=-4 in equation(1) we get,

»a+5×(-4)=-10
»a-20=-10
»a=-10+20
»a=10

Therefore, 15th term=a+(15-1)d
=10+14×(-4)
=10-56
=-46

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Answer 2

hope it help :).................