Question

This is the question...

Answer 1

Please make this brainliest answer if this helps!

$a = - 4 \\ l = 29 \\ \frac{n}{2} (a + l) = 150 \\ \frac{n}{2} (25) = 150 \\ n = 12 \\ \\ a + (n - 1)d = l \\ - 4 + (11)d = 29 \\ 11d = 33 \\ \\d = 3$

Answer 2

hey dear here is what you are looking for......

GIVEN

A 1= -4

An= 29

Sn = 150

D =?

answer.....



$sum \: = \: \frac{n}{2} (a1 \: + \: an)$
$150 = \frac{n}{2} ( - 4 + 29)$
$150 = \frac{n}{2} (25)$
$\frac{150 \times 2}{25} = \: n$
$12 = n$
An = A + (n-1) ×d
29= -4+(12-1)×d
29= -4+11×d
29+4=11×d
33÷11=d
3=d




hence the common difference is 3



hope it helps ❤❤❤✌✌✌