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Hey dear,
● Answer -
Volume of cylinder = 12.47 L
Weight of N2 = 7 g.
● Explanation -
On removal of CO2 weight drops by 22 gms. Hence, moles of CO2 present -
n1 = W1/M1 = 22/44 = 0.5
On removal of CO2 pressure changes from 1.5 atm to 0.5 atm -
X1 = ∆P/P° = 1/1.5 = 0.67
But,
X1 = n1 / (n1 + n2)
0.67 = 0.5 / (0.5 + n2)
n2 = 0.25
Weight of N2,
W2 = n2 × M2 = 0.25 × 28 = 7 g
Volume of cylinder can be calculated by -
V = nRT / P
V = (0.25 × 8.314 × 300) / (0.5×10^5)
V = 1.247×10^-2 m^3
V = 12.47 L
Therefore, volume of cylinder is 12.47 L & weight of N2 is 7 g.
Thanks for asking..
● Answer -
Volume of cylinder = 12.47 L
Weight of N2 = 7 g.
● Explanation -
On removal of CO2 weight drops by 22 gms. Hence, moles of CO2 present -
n1 = W1/M1 = 22/44 = 0.5
On removal of CO2 pressure changes from 1.5 atm to 0.5 atm -
X1 = ∆P/P° = 1/1.5 = 0.67
But,
X1 = n1 / (n1 + n2)
0.67 = 0.5 / (0.5 + n2)
n2 = 0.25
Weight of N2,
W2 = n2 × M2 = 0.25 × 28 = 7 g
Volume of cylinder can be calculated by -
V = nRT / P
V = (0.25 × 8.314 × 300) / (0.5×10^5)
V = 1.247×10^-2 m^3
V = 12.47 L
Therefore, volume of cylinder is 12.47 L & weight of N2 is 7 g.
Thanks for asking..
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