Question

This is the question of Direct and Inverse variation
Please solve the question b

Answer 1

Answer:

Step-by-step explanation

(a+b)'s one day work = 1/6

(b+c)'s one day work= 1/10

(c+a)'s one day work = 1/15

2(A+B+C)'s one day work = 1/6 + 1/10 + 1/15 = 1/3

        (a+b+c)'s one day work = 1/2 x 1/3 = 1/6

A+B+C together can finish the work in 6 days

    Now  A's one day work={(A+B+C)'s one day work} - {(B+C)'s one day work

                   = 1/6 - 1/10 =1/15

Hence, A alone can finish the work in 15 days.

B's one day work={(a+b+c)'s one day work}-(c+a)'s one day work}

                  = 1/6 - 1/15 = 1/10

Hence, B alone can finish work in 10 days.