This is the question of properties of parallel line..
Please solve the 2 question
Answers
Answer:
angles 1 and 2 are in ratio5:7 so let angle 1 be 5x and angle 2 be 7x
angle1+angle2=180°
5x +7x =180°
12x =180°
x=15°
therefore angle 1 =5x =5×15=75
angle 2 =7x=7×15=95
angle 1 =angle3 as vertically opposite angles are equal
so angle 3 =75°
angle 2=angle 6 =95° as corresponding angles are equal
angle 6=angle8=95° as opposite angles are equal
therefore, angle1=75° angle2=95° angle 3=75° and angle 8 = 95°
Q-2
ratio of angle(2) and angle(1) = 5:7
let angle (2) = 5x
let angle(1) = 7x
according to the given fig
angle(2) + angle (1) = 180°
5x + 7x = 180°
x = 180/12
x = 15
so,
angle(1) = 5×15
angle(1) = 75°
and,
angle(2) = 7× 15
angel(2) = 105°
angle(1) = angle (3) [vertically opposite angles are equal]
angle (3) = 75°
angle(3) = angle(5). [alternative interior angles]
so angle(5) = 75°
angle(5) +angle(8) = 180°
angle(8) = 180° - 75°
angle(8) = 105°
therefore
angle (1) = 75°
angle(2) = 105°
angle (3) = 75°
angle(8) = 105°
I hope this answer will help you
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