this is the question of surface area and vol
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let speed of stream is x km/h
according to question to question ,
24/(18-x) - 24/(x+18) =1
24{x+18-18+x}/(324-x^2) =1
48x =324 -x^2
x^2 +48x -324 =0
x = {-48 +√(2304 +1296)}/2
=6 km/h
hope it helped :-)
Let n be the larger tap. Then the smaller tap would be n+10.
So:
1/n+1/(n+10)=1/(75/8)=8/75
75(n+10)+75n=8n²+80n
8n²-70n-750=0
4n²-35n-375=0
(4n+25)(n-15)=0
n=15,-25/4
Throwing out the negative result, we get the bigger tap filling the tank in 15 hours, and the smaller tap in 25 hrs..
second answer if u needed
according to question to question ,
24/(18-x) - 24/(x+18) =1
24{x+18-18+x}/(324-x^2) =1
48x =324 -x^2
x^2 +48x -324 =0
x = {-48 +√(2304 +1296)}/2
=6 km/h
hope it helped :-)
Let n be the larger tap. Then the smaller tap would be n+10.
So:
1/n+1/(n+10)=1/(75/8)=8/75
75(n+10)+75n=8n²+80n
8n²-70n-750=0
4n²-35n-375=0
(4n+25)(n-15)=0
n=15,-25/4
Throwing out the negative result, we get the bigger tap filling the tank in 15 hours, and the smaller tap in 25 hrs..
second answer if u needed
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