this is the question of trigonometry please solve this problem
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sin(50°+theta) -cos(40°+theta)=0
we know that sin (50°+theta=90°)&cos(40°+theta=90°)
so,sin(theta=40°)-cos(theta=50°)
sin40°-cos50°
sin(90°-50°)-cos50°
cos50°-cos50°
0
hence proved.
we know that sin (50°+theta=90°)&cos(40°+theta=90°)
so,sin(theta=40°)-cos(theta=50°)
sin40°-cos50°
sin(90°-50°)-cos50°
cos50°-cos50°
0
hence proved.
priyankbhardwaj:
am i right
absolutely right
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