Question

this is the question...
you can see in class 10th ncert book ch-3 ex-3.6 question 4 of 1.
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2 \\ \frac{6}{x - 1 } - \frac{3}{y - 2} = 1$

if i let...
$\frac{1}{x -1 } =a , \frac{1}{y-2} =b$
then eqn is...

5a + b = 2 ------eqn 3rd
6a + 3b = 1 -------eqn 4th

then solve it by elemination method...


ans is x=4 and y=5


guy's please solve it correctly...


type karne me bhot time lga so please faltu ki bakwas na karte hue correct ans do
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Answer 1

Step-by-step explanation:

Substituting 1/(x-1) = a and 1/(y-2) = b in the given equations, we get,

5a + b = 2 …………………………(i)

6a – 3b = 1 ……………………….(ii)

Multiplying equation (i) by 3, we get

15a + 3b = 6 …………………….(iii)

Adding (ii) and (iii) we get

21a = 7

a = 1/3

Putting this value in equation (i), we get

5×1/3 + b = 2

b = 2- 5/3 = 1/3

a = 1/ (x-1)

⇒ 1/3 = 1/(x-1)

⇒ x = 4

b = 1/(y-2)

⇒ 1/3 = 1/(y-2)

⇒ y = 5

Hence, x = 4 and y = 5

Hope you got your answer

Have a great day ahead

Take care

Btw, In ur question eq.(4) is wrong..

it's - 3b