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1) angle D=3x+50°
angle B=80°
the sum of all angles in a quadrilateral is 360.
3x+50°+80°=180°
3x=180-130
x=50/3
x=16.66
here we taken sum of two angles only kk na u understand that
2) angle A=90°[since, the right angle=90°]
angle B=x
angle C=56°
angle D=x
sum of all angles=360°
90°+x+56°+x=360°
2x+146°=360°
2x=360-146
x=214/2
x=107°
sorry i don't know the 3rd question
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Question number 1, 2, 3 are in the attachment.
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