Question

This is trinometry question from geometry​

Answer 1

$\tan(b) = \frac{P}{B} = \frac{12}{9} \\ \\ = \boxed{\frac{4}{3} }$

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$\cos(b) = \frac{B}{H} = \frac{15}{20} \\ \\ = \boxed {\frac{3}{4} }$

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I HOPE IT HELPED.

Answer 2

Answer:

tan b= 12/9

cos b=20/25

Step-by-step explanation:

tan x = opposite side/adjacent side

tan b =12/9

cos x = adjacent side /hypotenuse

cos b = 20/25