This is under Logarithms
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Step-by-step explanation:
Given,
3^x+2=3^x+3^2
log3^x+2=log3^x+log3^2
x+2log3=xlog3+2log3
x+2log3-xlog3=2log3
x(1+2log3-log3)=2log3
x=2log3/(1+2log3-log3)
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