Question

THIS IS URGENT PLZ SOLVE IT MATHS CLASS 9
Two triangles on different basis in the same parallelogram have same areas. Explain. Please answer this don't spam​

Answer 1

Perimeter of Triangle

2S=26+28+30=84

⇒S=42cm

Area s(s−a)(s−b)(s−c) (Heron's formula)

Area =42(42−26)(42−28)(42−30)=42×16×14×12

Area=336cm2

Area of parallelogram = Area of triangle

⇒ h×28=336

⇒h=12cm

Height of parallelogram =12cm

Step-by-step explanation:

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