this is write question
Attachments:
Answers
Answered by
1
We know that radius is perpendicular to Tangent.
Therefore, Angle 0AT = 90°
50° + Angle OAB = 90°
Angle OAB = Angle OBA = 40° [Angle opp. to equal sides are equal]
Now in ∆OBA:
x° + 40° + 40° = 180° [Sum of Angle of A Triangle]
x° = 100° (Ans)
Therefore, Angle 0AT = 90°
50° + Angle OAB = 90°
Angle OAB = Angle OBA = 40° [Angle opp. to equal sides are equal]
Now in ∆OBA:
x° + 40° + 40° = 180° [Sum of Angle of A Triangle]
x° = 100° (Ans)
pritam143mandapcls6a:
ans:50
Similar questions