Question

This might be clearer... please answer all the questions from 11-15. Best answer will get brainliest.

Answer 1

11)(i)AD║BC

∴∠ADB=∠DBC              (Co-interior angles)

∠DBC=65°

(ii)In ΔBDC,

∠BCD+∠BDC+∠DBC=180              (Angle Sum Property)

50+∠BDC+65=180

     ∠BDC=180-115

      ∠BDC=65

(iii)Also,

AB║CD

∴∠ABD=∠BDC              (Co-interior angles)

 ∠ABD=65

(iv)In parallelogram opposite angles are equal.

  ∠A=50

12)(i)In ΔBDC,

∠BDC+∠BCD+∠DBC=180                     (Angle sum property)

100+25+∠DBC=180

             ∠DBC=55

(ii)DE║BC

∠EDC=∠DCB

∠EDC=25

(iii)Again,

DE║BC

∠ADE=∠ABC

∠ADE=55

(iv)In ΔADE,

55+55+AED=180        (Angle Sum Property)

AED=70

(v)AED+DEC=180          (Linear Pair)

           DEC=110