Question

this number are in the ratio 1 ratio 2 ratio 3 and some of their cube some is 4500 find numbers​

Answer 1

Let the numbers be x, 2x and 3x.

${x}^{3} + {8x}^{3} + {27x}^{3} = 4500 \\ \\ {36x}^{3} = 4500 \\ \\ {x}^{3} = \frac{4500}{36} \\ \\ x = \sqrt[3]{125} = 5 Answer$