this one bledy question buddies check it out
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if Reminder is perpendicular to x-axis then Reminder is y = 0 s//y if it is perpendicular to y-axis then remainder is x = 0
X u..?
11.
asal x asis enduk ochindi madyalo
Sorry dear, I can't understand this language
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i will translate why x axis came in between
wt?
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Something about question:- Here it is misprint in question as Remainder ⊥ given. It a mistake for sure. There is not any term like this.Instead of this remainder should be number, expression or etc like 1 , x +1 , 3, or whatever.
Here we are taking remainder as 1
Answer: = x³ + x² + 5x + 6
Step-by-step explanation:
Given,
Divisior = x + 1
Quotient = x² + 5
Remainder = 1
Dividend = ?
We know that,
Dividend = (Divisior × Quotient) + Remainder
Dividend = (x² + 5)(x + 1) + 1
= (x² × x) + (x² × 1) + (5 × x) + (5 × 1) +1
= x³ + x² + 5x + 5 + 1
= x³ + x² + 5x + 6
Here we are taking remainder as 1
Answer: = x³ + x² + 5x + 6
Step-by-step explanation:
Given,
Divisior = x + 1
Quotient = x² + 5
Remainder = 1
Dividend = ?
We know that,
Dividend = (Divisior × Quotient) + Remainder
Dividend = (x² + 5)(x + 1) + 1
= (x² × x) + (x² × 1) + (5 × x) + (5 × 1) +1
= x³ + x² + 5x + 5 + 1
= x³ + x² + 5x + 6
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