Question

this one is easy let see who will answer it​

Answer 1

Answer: v = 7.5 m/s.

Explanation:

Assume that the system is isolated.

Total momentum before collision = Total momentum after collision.

We know,

$\rm m_A u_A + m_B u_B = m_A v_A + m_B v_B$

=> (2 kg)(10 m/s) + (2 kg)(5 m) = (2 kg)v + (2 kg)v

[Combined velocity will be equal.]

=> 2v = (10 + 5) m/s

=> v = 15/2 m/s

=> v = 7.5 m/s.

Therefore, combined velocity after collision is equal to 7.5 m/s.