Question

This puzzel's solution

Answer 1

two vectors can have equal magnitude and can form an angle teta if they are part of a right angle triangle. To put it simply,

FOR MAGNITUDE:

R(Resultant vector)=((A)^2+(A)^2)1/2

R=(2A^2)^1/2

R=(2)^1/2 × A

it can be written as, R~A or R=A

FOR ANGLE;

tetha=tan^-1(A÷A)

tetha=tan^-1(1)

tetha=45°

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