Question

​this question answer please

Answer 1

Answer :

LHS = (cosecA+cotA)²

= [1/sinA + cosA/sinA]²

= (1/sin²A)[1+cosA]²

= (1/sin²A)[1+1/secA]²

= (1/sin²A)[(secA+1)/secA]²

= (1/sin²Asec²A)(secA+1)²

= (1/tan²A)(secA+1)²

= (secA+1)²/(sec²A-1)

= (secA+1)²/[(secA+1)(secA-1)]

= (secA+1)/(secA-1)

= RHS

Hope it's help you ☑️☑️