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length (l)=10 and breath (b)=8
Step-by-step explanation:
let the length be l and breadth be b so area equal be l×b
so first case equation
(l+1)×(b+5)=l×b+63
lb+5l+b+5=lb+63
5l+b=58 ×2
10l+2b=116
or 2b=116-10l ....eq.1
and second case equation
(l+2)×(b+3)=l×b+52
lb+3l+2b+6=lb+52
or 3l+2b=46
using eq. 1 here
3l+(116-10l)=46
-7l=46-116
-7l=-70
l=10
putting in l value in eq.1
2b= 116-10×10
2b= 16
b=8
hope this will be helpful
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