Question

. THIS QUESTION HAS SIX PARTS (a to f). A piece of ribbon 30cm long is cut into three pieces. The first piece is x cm long. The second piece is two cm more than the length of the first piece. The third piece is twice as long as the first piece of ribbon. (a) Write an algebraic expression for the second piece of ribbon. *
1 point

This is a required question
(b) Write the ALGEBRAIC EXPRESSION for the third piece of ribbon. *
1 point
(c) Write the simplified ALGEBRAIC EXPRESSION for the total length of the three pieces of ribbon. *
2 points
(d) Write the ALGEBRAIC EQUATION that shows the total length of the three pieces of ribbon. *
1 point
(e) Solve the equation of part (d) to find the value of x. *
2 points
(f) State the length of EACH of the three pieces of ribbon. *
3 points

Answer 1

Answer:

let length of Ribbon B l

Therefore

L=30

Ribbons cutted in ratio 5 is to 3

Therefore length of ribbonS

Be 30*5

=150

And 3*30=90

Therefore lengths of ribbons be 150 and 90

Answer 2

Answer:

a) x+2

b)x+x

c) (X) + (x+2) + (X+X)

d) (X) + (x+2) + (X+X)

e) value of x = 7 cm

f) 1st piece =7 cm

  2 piece = 9 cm

   3 piece =14 cm

Step-by-step explanation: