This question I'm sending a picture
Attachments:
Answers
Answered by
3
Let theta be A since it's not on my keyboard
sin A - 2sin³A / 2cos³ - cos A
= sin A ( 1 - 2 sin²A ) / cos A ( 2cos²A - 1 )
= sin A ( 1 - cos²A - 1 - sin²A ) / cos A ( cos²A + 1 - sin²A - 1 )
= sin A ( cos²A - sin²A ) / cos A ( cos²A - sin²A )
= sin A / cos A
= tan A
HOPE IT IS MOST HELPFUL!!!!!!!!!!!!
sin A - 2sin³A / 2cos³ - cos A
= sin A ( 1 - 2 sin²A ) / cos A ( 2cos²A - 1 )
= sin A ( 1 - cos²A - 1 - sin²A ) / cos A ( cos²A + 1 - sin²A - 1 )
= sin A ( cos²A - sin²A ) / cos A ( cos²A - sin²A )
= sin A / cos A
= tan A
HOPE IT IS MOST HELPFUL!!!!!!!!!!!!
Similar questions