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Anonymous:
i have the solution. resend the question
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Answered by
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Let the unit digit be x and ten's digit be y.
Then, the number becomes = 10y + x
According to the question,
x + y = 11 --> { i }
x = 11 - y
Also, ( 10 x + y ) - ( 10y + x ) = 27 --> ( ii )
10x + y - 10y - x = 27
9x - 9y = 27
9 ( x - y ) = 27
( x - y ) = 27 / 9 = 3
Putting value of x,
( 11 - y ) - y = 3
11 - 2y = 3
-2y = 3 - 11
-2y = - 8
y = 8 /2 = 4
Putting value of y in X,
x = 11 - y = 11 - 4 = 7
Now, placing values of x and y in the Number = 10y + x
=> 10 × 4 + 7 = 40 + 7 =
Then, the number becomes = 10y + x
According to the question,
x + y = 11 --> { i }
x = 11 - y
Also, ( 10 x + y ) - ( 10y + x ) = 27 --> ( ii )
10x + y - 10y - x = 27
9x - 9y = 27
9 ( x - y ) = 27
( x - y ) = 27 / 9 = 3
Putting value of x,
( 11 - y ) - y = 3
11 - 2y = 3
-2y = 3 - 11
-2y = - 8
y = 8 /2 = 4
Putting value of y in X,
x = 11 - y = 11 - 4 = 7
Now, placing values of x and y in the Number = 10y + x
=> 10 × 4 + 7 = 40 + 7 =
Answered by
1
I hope 47 is the answer
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