Question

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Answer 1

Answer:

this is the answer of 3rd (ग)

Explanation:

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Answer 2

Answer:

Given :

(1)3+(2)3²+(3)3³+...+(n)3^n =[(2n-1)(3)^(n+1) +3]/4

To find:

Prove that by using the method Mathematical Induction ?

Solution :

Given that :

(1)3+(2)3²+(3)3³+...+(n)3^n =[(2n-1)(3)^(n+1) +3]/4

Put n = 1 then

(1)3¹ = [{(2×1)-1}(3)^(1+1)

=>3 =[(2-1)(3)²+3]/4

=> 3 = ((1)9+3)/4

=> 3 = 12/4

=> 3 = 3

This statement is true for n = 1

Now,