Question

This question is frm ncert book 10 th class chapter 1

REAL NUMBERS



PLZ...
I WANT CORRECT ANSWER WITH FULL METHOD.



HELP...


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Answer 1

Step-by-step explanation:

H.C.F of (60,120,288)

= 12( 5 , 10 , 24)

H.C.F = 12

60 = 5 × 2 × 2 × 3

120 = 5×2 × 2 × 3 × 2

288 = 3×2 × 2 × 2 ×2× 3 × 2

L.C.M = 2^5 × 3^2 × 5^1

= 32 × 9 × 5 = 1440

H.C.F = 12. , L.C.M = 1440 Answer

Answer 2

Answer:

HCF = 12

LCM = 1440

Step-by-step explanation:

Factors:

60 = 2*2*3*5

120 = 2*2*2*3*5

288 = 2*2*2*2*2*3*3

HCF by Prime Factorization

Find the prime factors of each of the given number.

Next, we identify the common prime factors of the given numbers.

We then multiply the common factors. The product of these common factors is the HCF of the given numbers

HCF = 2*2*3 = 12

LCM by Prime factorization

To the LCM using prime factorization method we need to follow the below-mentioned steps:

Find the prime factors of numbers individually.

From all the factors, identify the maximum number of times each prime factor appears.

The product of the prime factors occurring in maximum numbers is the LCM of the given set of numbers.