Question

this question is from 10th std 1st. Chp- Similarity

Answer 1

Solution...

In triangle POB and QOA
angle BOP = Angle AOQ ( V.O.A.)
Angle BPO = Angle AQO ( A.I.A.)
By A.A. similarly criteria.

POB is similar to QOA

We know that the area two similar triangles is equal to squares of their coressponding sides.
So,
➡Area (POB) ÷ Area ( QOA) =
( PO)square = (OQ) square
➡150 / Area (QOA) =
${5}^{2} \div {7}^{2}$
➡to solve,
we get,
Area (QOA) = 150×49 ÷25

➡ Area triangle QOA is 294cm squares.

HOPE THIS WILL HELP YOU..✌✌☺☺