Question

this question is from algebraic expression pls answer fast

Answer 1

Answer:

(i) 2809

(ii) 996004

(iii) 2491

(iv) 2860

(v) 94.06

(vi) 103.02

Step-by-step explanation:

(i) $(50+3)^{2}$

use identity $(x+y)^{2} = x^{2} + y^{2} + 2xy$

$50^{2} + 3^{2} + 2*50*3 = 2500 + 9 + 300 = 2809$

(ii) $(998)^{2}= (1000-2)^{2}$

use identity $(x-y)^{2} = x^{2} - 2xy + y^{2}$

$1000^{2} - 2*1000*2 + 2^{2} = 1000000 - 4000 + 4 = 996004$

(iii) 47 × 53 = (50 - 3) × (50 + 3)

using identity (a-b)(a+b) = $a^{2} -b^{2}$

  = $50^{2}-3^{2}$ = 2500 - 9 = 2491

(iv) 52 x 55 = (50+2) x (50+5)

using identity (x+a)(x+b) = $x^{2}$ + (a+b)x + ab

= $50^{2}$ + 7x50 + 10 = 2860

(v) using identity $a^{2}- b^{2} = (a-b)(a+b)$

   = (9.7-0.3)(9.7+0.3) = 94.06

Answer 2

Step-by-step explanation:

1. 2809
2. 996004
3. 2491
4. 2860
5. 94.06
6. 103.02