This question is from arithmetic
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30
Step-by-step explanation:
let first two digit number divisible by 3 is 12
last two digit number divisible by 3 is 99
hence A.P. is 12,15,18.....99.
let a = 12 and d ( common difference) = 15-12 =3
let's consider n as the numbers = 99
tn = a + (n-1)d
99= 12+(n-1)3
99= 12+3n - 3
99-12+3= 3n
90=3n
n=90÷3
n=30
hence the two digit number divisible by 3 is 30
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